Continue échantillonnage
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\boxed{x(nT_e) = \int_{-\infty}^{+\infty} p_{\tau}(t - nT_e) x(t) \dif t}
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\end{align*}
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Le temps de fermeture $\tau$ de l'interrupteur doit être le plus court possible.
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En faisant tendre $\tau$ vers 0, on obtient ainsi l'impulsion de Dirac~:
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\begin{multicols}{3}
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\begin{equation*}
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\lim\limits_{\tau\to 0} p_{\tau}(t-nT_e) = \delta(t-nT_e)
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\end{equation*}
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\columnbreak
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\begin{tikzpicture}
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\draw[help lines, dashed] (-1,-1) grid (3,3);
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\draw[-latex] (-0.5,0) -- (3,0) node[right]{$t$};
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\draw[-latex] (0,-0.5) -- (0,3) node[left]{$A$};
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\end{tikzpicture}
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\columnbreak
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\begin{tikzpicture}
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\draw[help lines, dashed] (-1,-1) grid (3,3);
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\draw[-latex] (-0.5,0) -- (3,0) node[right]{$t$};
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\draw[-latex] (0,-0.5) -- (0,3) node[left]{$A$};
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\end{tikzpicture}
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\end{multicols}
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\begin{align*}
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\lim\limits_{\tau\to 0} \int_{-\infty}^{+\infty} p_{\tau}(t-nT_e)x(t) \dif t
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&=\int_{-\infty}^{+\infty} \delta(t-nT_e)x(t) \dif t \\
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&= x(nT_e) \quad
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\text{(d'après les propriétés de l'impulsion de Dirac)}
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\end{align*}
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\paragraph{Le signal échantillonné}
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\end{document}
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