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Finish schema for RSA

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flyingscorpio@clevo 2022-01-31 12:55:52 +01:00
parent 6c9e9e13fa
commit 35ae939d9a
1 changed files with 16 additions and 20 deletions
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36
algebre-non-lineaire/main.tex
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@ -640,17 +640,10 @@
\subsection{Déchiffrement (clé privée)~: $(n,d)$}
émetteur espace public destinataire
partie privée ----> clé publique $(n,e)$ partie privée
formule de chiffrement message en clair $m$, $c=m^e [n]$
on doit déchiffrer c |
information privée <--------------------------------
clé privée (n,d)
\begin{center}
\begin{tikzpicture} % TODO finish
\begin{tikzpicture}
\node [rectangle,draw,thick]
(src) at (0,0)
(src) at (-5,0)
{\parbox{4cm}{\centering
émetteur \\
partie privée \\
@ -659,24 +652,27 @@
}}
;
\node (key) at (5,0) {\parbox{2.5cm}{\centering fonction de \\ chiffrement}};
\node [rectangle,draw,thick]
(dst) at (12,0)
(public) at (0,0)
{\parbox{4cm}{\centering
espace publique \\
clé publique $(n,e)$ \\
formule de chiffrement
}}
;
\node [rectangle,draw,thick]
(dst) at (5,0)
{\parbox{4cm}{\centering
destinataire \\
partie privée \\
message en clair $m$ \\
$c = m^e [n]$
}};
\draw [-latex]
(src) -- (key)
node[above,midway]{\parbox{2cm}{\centering$m$ \\ message \\ en clair}}
;
\draw [-latex]
(dst) -- (src)
node[above,midway]{\parbox{2cm}{\centering$m$ \\ message \\ en clair}}
}}
;
\draw [-latex] (src) -- (public);
\draw (dst.south) -- (5,-2);
\draw (5,-2) -- (-5,-2) node[above,midway]{$c$};
\draw [-latex] (-5,-2) -- (src);
\end{tikzpicture}
\end{center}